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5n^2+17n-40=0
a = 5; b = 17; c = -40;
Δ = b2-4ac
Δ = 172-4·5·(-40)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-33}{2*5}=\frac{-50}{10} =-5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+33}{2*5}=\frac{16}{10} =1+3/5 $
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